Find area parallelogram lines `y=mx, y=mx+1, y=nx and y=nx+1` equal to:

Area of the parallelogram formed by the lines y=mx,y=mx+1,y=nx and y=nx+1 equals to

The area of the parallelogram formed by the lines y=mx,y=xm+1,y=nx, and y=nx+1 equals.(|m+n|)/((m-n)^(2)) (b) (2)/(|m+n|)(1)/((|m+n|)) (d) (1)/((|m-n|))

Find the distance between the parallel lines y=mx+c and y=mx+d.

If y=mx+1 and y^(2)=4x+1 then m=

Find the value of m so that lines y=x+1, 2x+y=16 and y=mx-4 may be concurrent.

Find the distance between the two parallel straight lines y = mx + c and y = mx + d ? ["Assume" c gt d]

Find the value of m so that the straight lines y=x+1, y=2 (x+1) and y=mx+3 are concurrent.

If the area bounded by the curves y=x-x^(2) and line y=mx is equal to (9)/(2) sq.units,then m may be

Find the maximum area of the parallelogram inscribed in the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 one of whoe diagonals is the line y=mx.