Prove that the points whose coordinates are respectively (5,1), (1,-1) and (11,4) lie on a straight line and find its intercepts on the axes

Prove that the points (5,1),(1,-1) and (11,4) are collinear.Also find the eqints lie. these points lie.

The envelope of the family of straight lines whose sum of intercepts on the axes is 4 is

Prove that the points (4,3),(1,4)and (-2,5) are collinear. Also find out the equation of the straight line on which these points lie.

Locus of a point which is equidistant from the point (3,4) and (5,-2) is a straight line whose x -intercept is

Find the equation of the straight line drawn through the point of intersection of the lines x+y=4\ a n d\ 2x-3=1 and perpendicular to the line cutting off intercepts 5,6 on the axes.

The equation of the line through (4,1) , whose x-intercept is double its y- intercepts on the axes is

Find the equation of a line making intercept 4 and 5 on the coordinate axes .