Equation of a line is `3x-4y+10=0`. Find its (i) slope, (ii) x and yintercepts.

The slope of a line 3x-y+10=0

The equation of a line is 3x+4y-10=0 . Convert this equation into : (i) slope-intercept (ii) intercept (iii) perpendicular form

Find the equation of the line whose (i) slope=3 and y-intercept=5 (ii) slope=-1 and y-intercept=4 (iii) slope = -(2)/(5) and y-intercept=-3

The equation of a line is given by 4y-6x+9=0. Find the slope of other line which is perpendicular to it.

Transform the equation of the line sqrt(3)x+y-8=0 to (i) slope intercept form and find its slope and y-intercept (ii) intercept form and find intercepts in the coordinates axes (iii) normal form and find the inclination of the perpendicular segment from the origin on the line with the axis and its length.

Reduce the equation 6x+3y-5=0 to the slope-intercept form and find its slope and y-intercept.

Reduce the following equations into slope-intercept form and find their slopes and the y -intercepts. (i) x+7y=0 , (ii) 6x+3y-5=0 , (iii) y=0

Write the equations for the family of lines (i) with slope 3 (ii) with x -intercept 2 (iii) perpendicular to 2x-5y-6=0

Find the equation of the family of lines satisfying the following conditions : (i) passing through the origin (ii) parallel to the line 3x+4y+5=0 (iii) having slope 5 (iv) having y -intercept 4 .