Three sides `A B ,A Ca n dC A` of triangle `A B C` are`5x-3y+2=0,x-3y-2=0a n dx+y-6=0` respectively. Find the equation of the altitude through the vertex `Adot`

Three sides AB,AC and CA of triangle ABC are 5x-3y+2=0,x-3y-2=0 and x+y-6=0 respectively.Find the equation of the altitude through the vertex A.

The equations of the sides AB, BC and CA of a triangle ABC are x-2=0, y+1=0 and x + 2y - 4=0 respectively. What is the equation of the altitude through B on AC?

The equations of the sides A B ,\ B C\ a n d\ C A\ of\ "Delta"A B C\ a r e\ y-x=2,\ x+2y=1\ a n d\ 3x+y+5=0 respectively. The equation of the altitude through B is x-3y+1=0 b. x-3y+4=0 c. 3x-y+2=0 d. none of these

The equations of the sides AB,BC,CA of a triangle ABC are 2x-y-3=0,6x+y-21=0 and 2x+y-5=0 respectively.The external bisector of angle A passes through the point

The equations of the sides BC,CA and AB of the ABC are 2x+y+1=0,2x+3y+1=0 and 3x+4y+3=0 respectively.Find the equation of the perpendicular drawn from A on the side BC.

Equation of sides BC, CA and AB of triangle ABC are 7x+y-10=0,x+y+2=0 and x-2y+5=0 respectively.If D,E,F are mid-points of these sides and D',E',F' are foot of altitudes respectively,then tangent of the /_FD'E is

In a triangle ABC , if the equation of sides AB,BC and CA are 2x- y + 4 = 0 , x - 2y - 1 = 0 and x + 3y - 3 = 0 respectively , The equation of external bisector of angle B is

The equation of perpendiculars of the sides AB and AC of triangle ABC are x-y-4=0 and 2x-y-5=0 respectively.If the vertex A is (-2,3) and point of intersection of perpendicular bisectors is ((3)/(2),(5)/(2)) find the equation of medians to the sides AB& AC respectively

The equation of the altitudes AD,BE,CF of a triangle ABC are x+y=0,x-4y=0 and 2x-y=0 respectively.If.A =(t,-t) where t varies,then the locus of centroid of triangle ABC is (A) y=-5x(B)y=x(C)x=-5y(D)x=y