Find the equation of the straight line through `(a cos theta, b sin theta)` perpendicular to the line `x/(a cos theta)+ y/(b sin theta) = 1`.

The equation to the straight line passing through the point (a cos^(3)theta,a sin^(3)theta) and perpendicular to the line x sec theta+y csc theta=a is x cos theta-y sin theta=a cos2 thetax cos theta+y sin theta=a cos2 thetax sin theta+y cos theta=a cos2 theta none of these

The equation to the straight line passing through the point (a "cos"^(3) theta, a "sin"^(3) theta) and perpendicular to the line x "sec" theta + y"cosec" theta = a is

Equation of the plane which passes through the Z-axis, and is perpendicular to the line (x-a)/(cos theta) = (y-b)/(sin theta) =(z-c)/(0) is

What is the equation of the plane which passes through the z -axis and is perpendicular to the line (x-a)/(cos theta)=(y+2)/(sin theta)=(z-3)/(0)?(A)x+y tan theta=0(B)y+x tan theta=0(C)x cos theta-y sin theta=0(D)x sin theta-y cos theta=0

Find the equation of the normal to the curve x=a cos theta and y=b sin theta at theta

x=a cos theta,y=b sin theta then find dy/dx

If x cos theta + y sin theta =2 is perpendicular to the line x-y =3 then what is one of the value of theta ?

Eliminate theta from a sin theta + bcos theta = x "and" a cos theta -b sin theta = y