The sides AB and AD of a parallelogram ABCD are `2x-y+1=0 and x+3y-10=0` respectively and `C` is the point `(-1, -2)`. Find the equation of the diagonals AC and BD.

The equations of the perpendicular bisectors of the sides AB and AC of triangle ABC are x-y+5=0 and x+2y=0, respectively.If the point A is (1,-2) ,then find the equation of the line BC .

The equations of perpendicular bisectors of the sides AB and AC of a DeltaABC are x - y + 5 = 0 and x+2y = 0 , respectively. If the point A is (1, - 2) the equation of the line BC is

The equations of the perpendicular bisector of the sides AB and perpendicular bisector of the sides AB and AC of a /_ABC are x-y+5=0 and x+2y=0 respectively,if the point Ais (1,-2), then the equation ofthe line BC is

The sides AB and AC of a triangle ABC are respectively 2x+3y=29 and x+2y=16 respectively.If the mid-point of BCis(5,6) then find the equation of BC.

The equations of adjacent sides AB and AD of a parallelogram ABCD are 3x-4y+21=0 and 4x-3y-14=0 respectively.The perpendicular distances between the parallel sides AB,DC and AD,BC are (14)/(5) and (75)/(5) respectively.If the area of parallelogram is 2k . Find the value of k.

The sides AB and AC of a triangle ABC are respectively 2x+3y=29 and x+2y=16 respectively.If the mid-point of BC is (5,6) then find the equation of BC

Three sides AB,AC and CA of triangle ABC are 5x-3y+2=0,x-3y-2=0 and x+y-6=0 respectively.Find the equation of the altitude through the vertex A.

The equation of the side AB and AC of a triangle ABC are 3x+4y+9 and 4x-3y+16=0 respectively. The third side passes through the point D(5, 2) such that BD:DC=4:5 . Find the equation of the third side.