If the line `2x-y+1=0` touches the circle at the point `(2,5)` and the centre of the circle lies in the line `x+y-9=0.` Find the equation of the circle.

The line 2x-y+1=0 touches a circle at the point (2, 5) and the centre of the circle lies on x-2y=4 . The diameter (in units) of the circle is

The line 2x-y+1=0 is tangent to the circle at the point (2, 5) and the centre of the circle lies on x-2y=4. The square of the radius of the circle is

The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the center of the circle lies on x-2y=4. Then find the radius of the circle.

The line 5x-y=3 is a tangent to a circle at the point (2,7) and its centre is on theline x+2y=19. Find the equation of the circle.

The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the centre of the circles lies on x-2y=4. The radius of the circle is

The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the centre of the circles lies on x-2y=4. The radius of the circle is :

The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the centre of the circles lies on x-2y=4 The radius of the circle is:

A circle touches the lines x-y- 1 =0 and x -y +1 =0. the centre of the circle lies on the line

If centre of the circle lies on x+y=2 and it touches the line x=3 and y=2 . Find the dismeter of the circle.

A circle touches both the x-axis and the line 4x-3y+4=0 . Its centre is in the third quadrant and lies on the line x-y-1=0 . Find the equation of the circle.