Find the equation of the parabola whose focus is`(1,1)` and tangent at the vertex is `x+y=1.`

Prove that the equation of the parabola whose focus is (0, 0) and tangent at the vertex is x-y+1 = 0 is x^2 + y^2 + 2xy - 4x + 4y - 4=0 .

the equation of the parabola whose focus is the point (0,0) and the tangent at the vertix is x-y+1=0 is

the equation of the parabola whose focus is the point (0,0) and the tangent at the vertix is x-y+1=0 is

Find the equation of the parabola whose focus is at (-1, 1) and the directrix is x+y+1=0 .

The equation of the parabola whose focus is (1,1) and the directrix is x+y+1=0

Find the equation of the parabola whose focus is (4,-3) and vertex is (4,-1).

Find the equation of the parabola whose focus is (1,-1) and whose vertex is (2,1). Also find the axis and latusrectum.

find the equation of parabola whose focus is (5,2) and vertex is at (3,2)

Find the equation of the parabola whose focus is (–6, –6) and vertex (–2, 2).

Find the equation of the parabola whose focus is (3, 0) and vertex is (0, 0) .