The equation of the ellipse with its centre at `(1, 2)`, one focus at `(6, 2)` and passing through the point `(4, 6)` is-

The equation of the ellipse with its centre at (1, 2), focus at (6, 2) and passing through the point (4 ,6) is (x-1)^(2)/a^(2)+(y-2)^(2)/b^(2)=1, then

find the equation of ellipse having centre at (1,2), focus at (6,2) and it passes through (4,6) .

The equation of the hyperbola whose centre is (1,2), one focus is (6,2) and transverse axis 6 is

Find the equation of the ellipse with eccentricity 3/4 , foci on the y-axis, centre at the origin and passing through the point (6, 4).

An ellipse has its centre C(1,3) focus at S( 6, 3) and passing through the point P(4, 7) then The product of the lengths of perpendicular segments from the focii on tangent at point P is

An ellipse has its centre C(1,3) focus at S( 6, 3) and passing through the point P(4, 7) then If the normal at a variable point on the ellipse meets its axes in Q and R then the locus of the mid-point of QR is a conic with an eccentricity (e') then