The foci of a hyperbola coincide with the foci of the ellipse `(x^2)/(25)+(y^2)/9=1.` Find the equation of the hyperbola, if its eccentricity is 2.

The foci of a hyperbola coincide with the foci of the ellipse (x^(2))/(25)+(y^(2))/(9)=1 . If the eccentricity of the hyperbola is 2 , then the equation of the tangent of this hyperbola passing through the point (4,6) is

If the foci of (x^(2))/(a^(2))-(y^(2))/(b^(2))=1 coincide with the foci of (x^(2))/(25)+(y^(2))/(9)=1 and the eccentricity of the hyperbola is 2, then a^(2)+b^(2)=16 there is no director circle to the hyperbola the center of the director circle is (0,0). the length of latus rectum of the hyperbola is 12

If foci of (x^(2))/(a^(2))-(y^(2))/(b^(2))=1 coincide with the foci of (x^(2))/(25)+(y^(2))/(16)=1 and eccentricity of the hyperbola is 3. then

The foci of the hyperbola (x^(2))/(16) -(y^(2))/(9) = 1 is :

Find th equation of the hyperbola eccentricity is 2 and the distance between foci 16.