The equations of the parabolas the extremities of whose latus rectum are `(3, 5)` and `(3,-3)`

Find the equation of the parabola the extremities of whose latus rectum are (1,2) and (1,-4).

Equation of parabola having the extremities of its latusrectum as (3,4) and (4,3) is

Find the equation of the ellipse the extremities of whose minor axis are (3, 1) and (3, 5) and whose eccentricity is 1/2 .

Find the equation of the parabola having (3,-6) and (3,6) as the extremities of the latus rectum .

If the vertex =(2,0) and the extremities of the latus rectum are (3,2) and (3,-2), then the equation of the parabola is:

Find the equation of the hyperbola , the length of whose latus rectum is 4 and the eccentricity is 3.

Let A be the vertex and L the length of the latus rectum of the parabola,y^(2)-2y-4x-7=0 The equation of the parabola with A as vertex 2L the length of the latus rectum and the axis at right angles to that of the given curve is:

Find the equation of the parabola whose vertex is (2,3) and the equation of latus rectum is x=4. Find the co-ordinates of the point of intersection of this parabola with its latus rectum.