the equation of perpendicular bisectors of side `AB,BC` of triangle `ABC` are `x-y=5 , x+2y=0` respectively and `A(1,-2)` then coordinate of `C`

The equation of perpendicular bisectors of the side AB and AC a triangle ABC are x-y+5=0 and x+2y=0 respectively vertex A is (1,-2) Area of triangle ABC is (in sq.units) (A) (36)/(5) (B) (18)/(5) (C) (72)/(5) (D) None of these

The equations of the perpendicular bisectors of the sides AB and AC of triangle ABC are x-y+5=0 and x+2y=0, respectively.If the point A is (1,-2) ,then find the equation of the line BC .

The equations of the perpendicular bisectors of the sides AB&AC of a triangle ABC are x-y+5=0&x+2y=0. find the equation of the bc

The equations of perpendicular bisectors of two sides AB and AC of a triangle ABC are x+y+1=0 and x-y+1=0 respectively. If circumradius of Delta ABC is 2 units, then the locus of vertex A is

The equation of the perpendicular bisector of the side AB of a triangle ABC is x-y+5=0 . If the point A is (1,2) , find the co-ordinates of the point B .

The equation of perpendiculars of the sides AB and AC of triangle ABC are x-y-4=0 and 2x-y-5=0 respectively.If the vertex A is (-2,3) and point of intersection of perpendicular bisectors is ((3)/(2),(5)/(2)) find the equation of medians to the sides AB& AC respectively

Let the equations of perpendicular bisectors of sides AC and of Delta ABCbe x+y=3 and x-y=1 respectively Then vertex A is is (0,0) The orthocentre of DeltaABC is

The equations of the perpendicular bisector of the sides AB and perpendicular bisector of the sides AB and AC of a /_ABC are x-y+5=0 and x+2y=0 respectively,if the point Ais (1,-2), then the equation ofthe line BC is