Two sides of a rhombus lying in the first quadrant are given by `3x-4y=0a n d12 x-5y=0` . If the length of the longer diagonal is 12, then find the equations of the other two sides of the rhombus.

Two sides of a rhombus lying in the first quadrant are given by 3x-4y=0 and 12x-5y=0. If the length of the longer diagonal is 12, then find the equations of the other two sides of the rhombus.

The lengths of the diagonals of a rhombus are 16 cm and 12 cm. Then, the length of the side of the rhombus is

Two consecutive sides of a parallelogram are 4x+5y=0 and 7x+2y=0. If the equation of one diagonal is 11x=7y=9, find the equation of the other diagonal.

The lengths of the diagonals of a rhombus are 16 cm and 12 cm . The length of each side of the rhombus is

Each side of a rhombus is 10 cm long and one of its diagonals measures 16 cm. Find the length of the other diagonal and hence find the area of the rhombus.

The diagonals of a rhombus are 16cm and 12cm. Find the length of each side of the rhombus.

The combined equation of two adjacent sides of a rhombus formed in first quadrant is 7x^(2)-8xy+y^(2)=0 then slope of its longer diagonal is

Two adjacent sides of a rhombus are given by 2x^(2)-47xy+2y^(2)=0 .If length of the shorter diagonal passing through their point of intersection is 10sqrt(2) Then find the total number of possible positions of the vertex lying on it other than origin.