If the point `A` is symmetric to the point `B(4,-1)` with respect to the bisector of the first quadrant then `AB` is

If the point A is symmetric to the point B(4,-1) with respect to the bisector of the first quadrant, then the length of AB is:

Statement -: Point Q is symmetric to point P(4,-3) with respect to bisector of first and third quadrantthen the length of PQ is 7sqrt2 Statement-2: Bisector of the first and third quadrant is perpendicular bisector of PQ.

Through the point (4,1) and making with the axes in the first quadrant a triangle whose area is 8.

Joint equation of the X-axis and the bisector of the angle in the first quadrant is

Let A-=(-4, 0), B -= (-1, 4). C and D are points which are symmetric to points A and B respectively with respect to y-axis, then area of the quadrilateral ABCD is (A) 8 sq units (B) 12 sq. units (C) 20 sq. units (D) none of these

In which quadrant does the point (-4,-3) lies.

Tangent drawn from the point P(4,0) to the circle x^(2)+y^(2)=8 touches it at the point A in the first quadrant.Find the coordinates of another point B on the circle such that AB=4.

A(-4,0) and B(-1,4) are two given points.Cand D are points which are symmetric to the given points A and B respectively with respect to y- axis.Calculate the perimeter of the trapezium ABDC.

If A is symmetric, show that B' AB is symmetric.