If `a, b, c` are variables such that `21a + 40b + 56c=0` then the family of lines `ax+by+c=0` passes through (A) `(7/14, 9/4)` (B) `(4/7, 3/8)` (C) `(3/8, 5/7)` (D) `(2, 3)`

If 3a+2b+4c=0 then the lines ax+by+c=0 pass through the fixed point

If a,b,c are variables such that 3a+2b+4c=0, then show that the family of lines givenby ax+by+c=0 pass through a fixed point.Also,find that point.

If 6a^2-3b^2-c^2+7ab-ac+4bc=0 then the family of lines ax+by+c=0,|a|+|b| != 0 can be concurrent at concurrent (A) (-2,3) (B) (3,-1) (C) (2,3) (D) (-3,1)

In a family of 3 children, the probability of having at least one boy is 7/8 (b) 1/8 (c) 5/8 (d) 3/4

If a=7, b=5, c=3, then the value of a^2+b^2+c^2-a b-b c-c a i s -12 (b) 0 (c) 8 (d) 12

The algebraic sum of distances of the line ax + by + 2 = 0 from (1,2), (2,1) and (3,5) is zero and the lines bx - ay + 4 = 0 and 3x + 4y + 5=0 cut the coordinate axes at concyclic points. Then (a) a+b=-2/7 (b) area of triangle formed by the line ax+by+2=0 with coordinate axes is 14/5 (c) line ax+by+3=0 always passes through the point (-1,1) (d) max {a,b}=5/7

If a^(3) = 1 + 7, 4^(2) = 1 + 5 + b , 5^(3) = 1 + 8 + c , then the value of a + b + c is

(1) if a+b+c=0 the straight line 2ax+3by+4c=0 passes through the fixed point (2) if 3a+2b+4c=0 the straight line ax+by+c=0 passes through the fixed point