The equaiton of the line perpendicular to `2x+6y+5=0` and having the length of x-intercept equal to 3 units can be (A) `y=3x+5` (B) `2y=6x+1` (C) `y=3x+9` (D) none of these

Equation of the line belonging to the system 3x+2y-8+lambda(2x-5y+1)=0 and having equal intercepts is

If a line with y-intercept 2, is perpendicular to the line 3x -2y =6, then its x-intercept is

The length of the y-intercept made by the circle x^(2)+y^(2)-4x-6y-5=0 is

Find the equation of the line passing through (–3, 5) and perpendicular to the line through the points (2, 5) and (–3, 6). (a)5x-y+20=0 (b)6x-4y=9 (c)3x-5y-9=0 (d)None of these

If A=[(3 ,x), (y ,5)] and A=A^T then (A)x=0,y=5 (B)x+y=5 (C)x=y (D)none of these

The length of the intercept on y- axis cut off by the parabola,y^(2)5y=3x-6 is

The equaiton of the lines through the point (2, 3) and making an intercept of length 2 units between the lines y+2x=3 and y+2x=5 are (A) x+3=0, 3x+4y=12 (B) y-2=(0, 4x-3y=6 (C) x-2=0, 3x+4y=18 (D) none of these

3x - y= 5, 6x - 2y = 10 .