The point `(-4,5)` is vertex of a square and one of its diagonal is `7x-y+8=0.` The equation of other diagonal is `7x-y+23=0` `7y+x+=30` `7y+x=31` `x-7y=30` `x+7y+31=0`

If (-4,5) is a vertex of a square and one of its diagonal is 7x-y+8-0. Find the equation of other diagonal

The point (-4,5) is vertex of a square and one of its diagonal is 7x-y+8=0. The equation of other diagonal is 7x-y+23=07y+x+=307y+x=31x-7y=30x+7y+31=0

Two consecutive sides of a parallelogram are 4x+5y=0a d n7x+2y=0. If the equation of one diagonal is 11 x+7y=9, Equation of other diagonal : (A) 11x + 7y =0 (B) 3x - 5y + 5 = 0 (C) 7x + 11y = 0 (D) 3x + 5y + 5 =0

7y-x-5=0 touches the circle x^2+y^2-5x+5y=0. The equation of other parallel tangent is

If pairs of opposite sides of a quadrilateral are x^(2)-7x+6=0 and y^(2)-14y+40=0 then equations of its diagonals are

Two consecutive sides of a parallelogram are 4x+5y=0 and 7x+2y=0. If the equation of one diagonal is 11x=7y=9, find the equation of the other diagonal.

5x + 2y = 31 3x + 7y = 36