if `x/a+y/b=1` is a variable line where `1/a^2+1/b^2=1/c^2` (`c` is constant ) then the locus of foot of the perpendicular drawn from origin

A variable straight line passes through a fixed point (h,k). Find the locus of the foot of the perpendicular on it drawn from the origin.

If the line ((x)/(a))+((y)/(b))=1 moves in such a way that ((1)/(a^(2)))+((1)/(b^(2)))=((1)/(c^(2))), where c is a constant,prove that the foot of the perpendicular from the origin on the straight line describes the circle x^(2)+y^(2)=c^(2)

A straight line passes through a fixed point (2, 3).Locus of the foot of the perpendicular on it drawn from the origin is

A variable line cuts pair of lines x^(2)-(a+b)x+ab=0 in such a way that intercept between subtends a right angle at origin.The locus of the foot of the perpendicular from origin on variable line is

Find the coordinates of the foot of the perpendicular drawn from the point (1,-2) on the line y=2x+1

Two points A and B move on the positive direction of x-axis and y-axis respectively, such that OA + OB K. Show that the locus of the foot of the perpendicular from the origin O on the line ABís (x + y)(x2 + y2) = Kxy. · (0,b)B Let the equation of AB be =1 a