The equation of sides `BC, CA, AB` of a triangle `ABC` are `ax+by+c=0, lx + my + n=0` and `px+qy+r=0` respectively, then the line : `(px+qy+r)/(ap+bq) = (lx+my+n)/(al+mb)` is (A) perpendicular to AB (B) perpendicular to AC (C) perpendicular to BC (D) none of these

The equations of the sides AB, BC and CA of a triangle ABC are x-2=0, y+1=0 and x + 2y - 4=0 respectively. What is the equation of the altitude through B on AC?

the equation of perpendicular bisectors of side AB,BC of triangle ABC are x-y=5,x+2y=0 respectively and A(1,-2) then coordinate of C

The equations of the perpendicular bisectors of the sides AB&AC of a triangle ABC are x-y+5=0&x+2y=0. find the equation of the bc

The equations of the perpendicular bisectors of the sides AB and AC of triangle ABC are x-y+5=0 and x+2y=0, respectively.If the point A is (1,-2) ,then find the equation of the line BC .

In Delta ABC equation of the right bisectors of the sides Ab and AC are x+y = 0 and x - y = 0 respectively .If A = (5,7) then equation of side BC is

The equation of perpendiculars of the sides AB and AC of triangle ABC are x-y-4=0 and 2x-y-5=0 respectively.If the vertex A is (-2,3) and point of intersection of perpendicular bisectors is ((3)/(2),(5)/(2)) find the equation of medians to the sides AB& AC respectively

The vertices of a triangle ABC are the points (0, b), (-a, 0), (a, 0) . Find the locus of a point P which moves inside the triangle such that the product of perpendiculars from P to AB and AC is equal to the square of the perpendicular to BC .