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Find the equation of the circle passing ...

Find the equation of the circle passing through the point of intersection of the circles `x^2 + y^2 - 6x + 2y + 4 = 0, x^2 + y^2 + 2x - 4y -6 = 0` and with its centre on the line `y = x.`

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The equation of the circle passing through the point of intersection of the circles x^2 + y^2 - 6x + 2y + 4 = 0 and x^2 + y^2 + 2x - 6y - 6=0 and having its centre on y=0 is : (A) 2x^2 + 2y^2 + 8x + 3 = 0 (B) 2x^2 + 2y^2 - 8x - 3 = 0 (C) 2x^2 + 2y^2 - 8x + 3 = 0 (D) none of these

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The equation of the circle passing through the points of intersection of the circles x^(2)+y^(2)+6x+4y-12=0,x^(2)+y^(2)-4x-6y-12=0 and having radius sqrt(13)" is

The equation of the circle passing through the points of intersection of the circles x^(2)+y^(2)+6x+4y-12=0 , x^(2)+y^(2)-4x-6y-12=0 and having radius sqrt(13) is

The equation of the circle passing through the points of intersection of the circles x^(2)+y^(2)+6x+4y-12=0,x^(2)+y^(2)-4x-6y-12=0 and having radius sqrt(13) is

The equation of the circle passing through the points of intersection of the circles x^(2)+y^(2)+6x+4y-12=0 , x^(2)+y^(2)-4x-6y-12=0 and having radius sqrt(13) is