If `4l^2-5m^2+6l+1=0.` Prove that `lx+my+1=0` touches a definite circle. Find the centre & radius of the circle.

if 4alpha^2-5beta^2+6alpha+1=0 , Prove that alphax+betay+1=0 touches a definite circle, Find the centre and radius of the circle.

A line is tangent to a circle if the length of perpendicular from the centre of the circle to the line is equal to the radius of the circle. If 4l^2 - 5m^2 + 6l + 1 = 0 , then the line lx + my + 1=0 touches a fixed circle whose centre. (A) Lies on x-axis (B) lies on yl-axis (C) is origin (D) none of these

If 4a^(2)-5b^(2)+6a+1=0 and the line ax+by+1=0 touches the fixed circle then (a) Centre of circle at (3,0) (b) radius of circle is sqrt(5) (c) radius of circle is sqrt(3) (d) circle passes through (1,1)

If 1x+my-1=0 touches the circle x^(2)+y^(2)=a^(2) then the point (1,m) lies on the circle

If the line lx+my-1=0 touches the circle x^(2)+y^(2)=a^(2), then prove that (l,m) lies on a circle.

Consider the relation 4l^(2)-5m^(2)+6l+1=0 , where l, m inR . The line lx+my+1=0 touches a fixed circle whose equation is

Prove that the points (1,-6), (5,2) , (7,0) and (-1,-4) are concyclic. Find the radius of the circle .

If the line 2x-y+1=0 touches the circle at the point (2,5) and the centre of the circle lies in the line x+y-9=0. Find the equation of the circle.