The tangent at the point `(alpha, beta)` to the circle `x^2 + y^2 = r^2` cuts the axes of coordinates in `A and B`. Prove that the area of the triangle `OAB` is `a/2 r^4/|alphabeta|, O` being the origin.

Let (a, b) is the midpoint of the chord AB of the circle x^2 + y^2 = r^2. The tangents at A and B meet at C, then the area of triangle ABC

The area of the triangle formed by the tangent at the point (a, b) to the circle x^(2)+y^(2)=r^(2) and the coordinate axes, is

The area of the triangle formed by the tangent at the point (a,b) to the circle x^(2)+y^(2)=r^(2) and the co-ordinate axes is:

The line 7x+4y=28 cuts the coordinate axes at A and B. If O is the origin,then the ortho-centre of OAB is

If the plane (x)/(2)+(y)/(3)+(z)/(4)=1 cuts the coordinate axes in A,B,C, then the area of triangle ABC is

Tangent at a point on the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 is drawn which cuts the coordinates axes at A and B the maximum area of the triangle OAB is ( O being origin )

Normal is drawn at one of the extremities of the latus rectum of the hyperbola (x^(2))/(a^(2))-(y^(2))/(b^(2))=1 which meets the axes at points A and B . Then find the area of triangle OAB(O being the origin).

If the tangent at a point on the ellipse (x^(2))/(27)+(y^(2))/(3)=1 meets the coordinate axes at A and B, and the origin,then the minimum area (in sq.units) of the triangle OAB is: