The equation of three circles are given `x^2+y^2=1,x^2+y^2-8x+15=0,x^2+y^2+10 y+24=0` . Determine the coordinates of the point `P` such that the tangents drawn from it to the circle are equal in length.

The equation of three circles are given x^(2)+y^(2)=1,x^(2)+y^(2)-8x+15=0,x^(2)+y^(2)+10y+24=0* Determine the coordinates of the point P such that the tangents drawn from it to the circle are equal in length.

The length of the chord of contact of the tangents drawn from the point (-2,3) to the circle x^2+y^2-4x-6y+12=0 is:

The equations of two circles are x^(2)+y^(2)+2 lambda x+5=0 and x^(2)+y^(2)+2 lambda y+5=0 .P is any point on the line x-y=0 .If PA and PB are the lengths of the tangents from P to the two circles and PA=3 them PB=

The equations of two circles are x^(2)+y^(2)+2 lambda x+5=0 and x^(2)+y^(2)+2 lambda y+5=0.P is any point on the line x-y=0. If PA and PB are the lengths of the tangent from Ptothe circles and PA=3 then find PB.

The radius centre of the circles x^(2)+y^(2)=1,x^(2)+y^(2)+10y+24=0andx^(2)+y^(2)-8x+15=0 is

The equation of the tangent to the circle x^(2) + y^(2) + 4x - 4y + 4 = 0 which makes equal intercepts on the coordinates axes in given by

Given three circles x^(2)+y^(2)-16x+60=03x^(2)+3y^(2)-36x+81=0 and x^(2)+y^(2)-16x-12y+84=0. Find (1) the points from which the tangents are equal in length and (2) this length.