If a circle cuts orthogonally three circles, `S_1 = 0, S_2=0, S_3=0`, prove that it cuts orthogonally and circle `kS_1 + lS_2 + mS_3 = 0`.

All those circles which pass through (2,0) and (-2,0) are orthogonal to the circle (s)

If a circle Passes through point (1,2) and orthogonally cuts the circle x^(2)+y^(2)=4, Then the locus of the center is:

If two circles of the same radius r and centres at (-1,2) and (3,6) respectively cut orthogonally,then the value of r is

Two circles which pass through the points A(0,a),B(0,-a) and touch the line y=mx+c wil cut orthogonally if

If the circle |z-1|=3 and |z-z_(0)|=4 intersect orthogonally,then

The equation of a circle S_1 is x^2 + y^2 = 1 . The orthogonal tangents to S_1 meet at another circle S_2 and the orthogonal tangents to S_2 meet at the third circle S_3 . Then (A) radius of S_2 and S_1 are in ratio 1 : sqrt(2) (B) radius of S_2 and S_1 are in ratio 1 : 2 (C) the circles S_1, S_2 and S_3 are concentric (D) none of these

Find the equation of the circle which cuts orthogonally the circle x^(2)+y^(2)6x+4y-3=0, passes through (3,0) and touches the axis of y.