Show that the four points of intersection of the lines : `(2x-y + 1)` `(x-2y+3) = 0`, with the axes lie on a circle and find its centre.

The four point of intersection of the lines ( 2x -y +1) ( x- 2y +3) = 0 with the axes lie on a circle whose center centre is at the point :

Find the point of intersection of the lines 2x-3y+8=0 and 4x+5y=6

Find the point of intersection of the line, x/3 - y/4 = 0 and x/2 + y/3 = 1

Find the point of intersection of the circle x^(2)+y^(2)-3x-4y+2=0 with the x -axis.

If a circle passes through the points of intersection of the lines 2x-y +1=0 and x+lambda y -3=0 with the axes of reference then the value of lambda is :

If (1, 4) is the point of intersection of the lines 2x + by = 6 and 3 y = 8 + ax , then find the value of a -b

If a circle passes through the points of intersection of the lines 2x-y+1=0 and x+lambda y-3=0 with the axes of reference then the value of lambda is

Find the point of intersection of the following pairs of lines: 2x-y+3=0 and x+y-5=0

(i) A circle whoe centre is the point of intersection of the line 2x - 3y + 4 - 0 and 3x + 4y - 5 = 0 passes through the origin. Find its equation. (ii) Find the equation of the circle passing through the point (1,-1) and centre at the intersection of the lines (x -y) = 4 and 2x + 3y = -7.