The two circles x^2 + y^2 -2x+6y+6=0 and...

The two circles `x^2 + y^2 -2x+6y+6=0 and x^2 + y^2 - 5x + 6y + 15 = 0` touch eachother. The equation of their common tangent is : (A) `x=13` (B) `y=6` (C) `7x-12y-21=0` (D) `7x+12y+21=0`

AI Generated Solution

Similar Questions

Explore conceptually related problems

Consider the circles x^(2) + y^(2) = 1 & x^(2) + y^(2) – 2x – 6y + 6 = 0 . Then equation of a common tangent to the two circles is

The circles x^(2)+y^(2)+6x+6y=0 and x^(2)+y^(2)-12x-12y=0

Show that the circles x^2 + y^2 - 2x-6y-12=0 and x^2 + y^2 + 6x+4y-6=0 cut each other orthogonally.

The circles x^(2)+y^(2)-4x-6y-12=0 and x^(2)+y^(2)+4x+6y+4=0

The two circles x^(2)+y^(2)-2x-3=0 and x^(2)+y^(2)-4x-6y-8=0 are such that

7y-x-5=0 touches the circle x^2+y^2-5x+5y=0. The equation of other parallel tangent is

Radii of circles x^(2) + y^(2) = 1, x^(2) + y^(2) - 2x - 6y= 6 and x^(2) + y^(2) - 4x - 12y = 9 are in