`f(x, y) = 0` is a circle such that `f(0, lambda) = 0 and f(lambda, 0)=0` have equal roots and `f(1, 1)= -2` then the radius of the circle is : (A) 4 (B) 8 (C) 2 (D) 1

Let f(x,y) =0 be the equation of a circle. If f (0, lamda)=0 has equal roots lamda=1,1 and f (lamda, 0 ) =0 has roots lamda =1/5 ,5, then the radius of the circle is

Let f(x,y)=0 be the equation of circle.If f(0,lambda)=0 has equal roots lambda=1,1 and f(lambda,0)=0 has roots lambda=(1)/(5),5 ,then the radius of the circle

Let f(x,y) =0 be the equation of a circle. If f (0, lamda)=0 has equal roots lamda=1,1 and f (lamda, 0 ) =0 has roots lamda =1/2 ,2, then the centre of the circle is

Let phi (x,y)=0 , be the equation of circle. If phi (0,lambda)=0 has equal roots lambda =2,2 and phi (lambda,0)=0 has roots lambda=4/5, 5 then the centre of the circle is :

Suppose f(x,y)=0 is the equation of a circle such that f(x,1)=0 has equal roots (each equal to 2) and f(1,x)=0 also has equal roots (each equal to zero). The equation of circle is

If f(x) is a quadratic expression such that f(1) + f(2) = 0, and -1 is a root of f(x) = 0 , then the other root of f(x) = 0 is :

[ If f(x)=|x|+|x-1|, then int_(0)^(2)f(x)dx equals- [ (A) 3, (B) 2, (C) 0, (D) -1]]

If f(x) is a quadratic expression such that f(1)+f(2)=0, and -1 is a root of f(x)=0, then the other root of f(x)=0 is :

Let f(x,y)=0 be equation of circle such that (0,0) satisfy it and have family of linces x-2-(lambda+3)y+lambda x as its normal,lambda in R if diameter of circle is k then k^(2)=

If f(0)=0,f'(0)=2, then the derivative of y=f(f(f(x))) at x=0 is 2(b)8(c)16 (d) 4