The equation of the circle which inscribes a suqre whose two diagonally opposite vertices are `(4, 2) and (2, 6)` respectively is : (A) `x^2 + y^2 + 4x - 6y + 10 = 0` (B) `x^2 + y^2 - 6x - 8y + 20 = 0` (C) `x^2 + y^2 - 6x + 8y + 25 = 0` (D) `x^2 + y^2 + 6x + 8y + 15 = 0`

Two circles x^(2) + y^(2) - 4x + 10y + 20 = 0 and x^(2) + y^(2) + 8x - 6y - 24= 0

y-1=m_1(x-3) and y - 3 = m_2(x - 1) are two family of straight lines, at right angled to each other. The locus of their point of intersection is: (A) x^2 + y^2 - 2x - 6y + 10 = 0 (B) x^2 + y^2 - 4x - 4y +6 = 0 (C) x^2 + y^2 - 2x - 6y + 6 = 0 (D) x^2 + y^2 - 4x - by - 6 = 0

Two circles x^(2) + y^(2) - 2x - 4y = 0 and x^(2) + y^(2) - 8y - 4 = 0

The equation of the circle passing through the point of intersection of the circles x^2 + y^2 - 6x + 2y + 4 = 0 and x^2 + y^2 + 2x - 6y - 6=0 and having its centre on y=0 is : (A) 2x^2 + 2y^2 + 8x + 3 = 0 (B) 2x^2 + 2y^2 - 8x - 3 = 0 (C) 2x^2 + 2y^2 - 8x + 3 = 0 (D) none of these

The equation of the circle which pass through the origin and cuts orthogonally each of the circles x^(2)+y^(2)-6x+8=0 and x^(2)+y^(2)-2x-2y-7=0 is

Determine whether the equation represent a circle or not : x^2 + y^2 + 6x - 8y + 50 = 0

Equation of the circle passing through A(1,2), B(5,2) such that the angle subtended by AB at points the circle is pi/4 is (A) x^2+y^2-6x-8=0 (B) x^2+y^2-6x-8y+17=0 (C) x^2+y^2 -6x+8=0 (D) x^2+y^2-6x+8y-25=0