The equation of the circle passing through the point of intersection of the circles `x^2+y^2-4x-2y=8` and `x^2+y^2-2x-4y=8` and the point `(-1,4)` is `x^2+y^2+4x+4y-8=0` `x^2+y^2-3x+4y+8=0` `x^2+y^2+x+y=0` `x^2+y^2-3x-3y-8=0`

The equation of the circle passing through the point of intersection of the circles x^(2)+y^(2)-4x-2y=8 and x^(2)+y^(2)-2x-4y=8 and (-1,4) is (a)x^(2)+y^(2)+4x+4y-8=0(b)x^(2)+y^(2)-3x+4y+8=0(c)x^(2)+y^(2)+x+y=0(d)x^(2)+y^(2)-3x-3y-8=0

The point of tangency of the circles x^(2)+y^(2)-2x-4y=0 and x^(2)+y^(2)-8y-4=0 is

Find the point of intersection of the circle x^(2)+y^(2)-3x-4y+2=0 with the x -axis.

The equation of the circle passing through the point of intersection of the circles x^2 + y^2 - 6x + 2y + 4 = 0 and x^2 + y^2 + 2x - 6y - 6=0 and having its centre on y=0 is : (A) 2x^2 + 2y^2 + 8x + 3 = 0 (B) 2x^2 + 2y^2 - 8x - 3 = 0 (C) 2x^2 + 2y^2 - 8x + 3 = 0 (D) none of these

Find the equation of the circle passing through the centre of the circle x^2 +y^2 -4x-6y=8 and being concentric with the circle x^2 +y^2 - 2x-8y=5 .

Circles x^(2)+y^(2)=4 and x^(2)+y^(2)-2x-4y+3=0

Find the equation of the circle through the points of interrection of the circles x^(2)+y^(2)-4x-6y-12=0 and x^(2)+y^(2)+6x+4y-12=0 and cutting the circle x^(2)+y^(2)-2x-4=0 orthogonally.

The equation of the circle having its centre on the line x+2y-3=0 and passing through the points of intersection of the circles x^(2)+y^(2)-2x-4y+1=0 and x^(2)+y^(2)-4x-2y+4=0 is