Home
Class 12
MATHS
One of the diameters of the circle circu...

One of the diameters of the circle circumscribing the rectangle ABCD is `4y=x+7`. If `A and B` are the points `(-3, 4) and (5, 4)` and slope of the curve `y = (ax)/(b-x)` at point `(1, 1)` be `2`, then centre of circle is : (A) `(a, b)` (B) `(b, a)` (C) `(-a, -b`) (D) `(a, -b)`

Promotional Banner

Similar Questions

Explore conceptually related problems

If the slope of the curve y=(ax)/(b-x) at the point (1, 1) is 2, then

One of the diameter of a circle circumscribing the rectangle ABCD is 4y=x+7, If A and B are the points (-3,4) and (5,4) respectively, then the area of rectangle is

One of the diameters of the circle circumscribing the rectangle ABCD is 4y = x + 7. If A and B are the points (-3, 4) and (5, 4) respectively, then find the area of the rectangle.

One of the diameters of circle circumscribing the rectangle ABCD is 4y=x+7 . If A and B are the points (-3,4) and (5,4) respectively and area of rectangle is p then p/4 is equal to

One of the diameters of the circle circumscribing the rectangle ABCD is 4y=x+y . If A and B are the points (-3, 4) and (5, 4) respectively, find the area of the rectangle and equation of the circle.

If the tangent to the curve y^(2)=ax^(2)+b at the point (2,3) is y=4x-5, then (a,b)=

2x-y+4=0 is a diameter of a circle which circumscribes a rectangle ABCD. If the coordinates of A, B are (4, 6) and (1, 9) respectively, find the area of this rectangle ABCD.

If the line y= 4x-5 toches to the curve y^(2) = ax^(3) +b at the point (2,3) then 7a +2b=

The slope of the tangent to the curve x^(3)-x+1 at the point where the curve cuts the Y axis is .. (A) 1 (B) -1 (C) 3 (D) -3