The equation of a circle of radius `1` touching the circles `x^2 + y^2 - 2 |x| = 0` is: (A) `x^2 + y^2 + 2sqrt(3x) - 2 = 0` (B) `x^2 + y^2 - 2sqrt(3)y+2=0` (C) `x^2 + y^2 + 2sqrt(3) y + 2 = 0` (D) `x^2 + y^2 + 2 sqrt(3) x + 2 = 0`

The equation of a circle of radius 1touching the circles x^(2)+y^(2)-2|x|=0 is x^(2)+y^(2)+2sqrt(2)x+1=0x^(2)+y^(2)-2sqrt(3)y+2=0x^(2)+y^(2)+2sqrt(3)y+2=0x^(2)+y^(2)-2sqrt(2)+1=0

Equation of a circle of radius 2 and touching the circles x^(2)+y^(2)-4|x|=0 is x^(2)+y^(2)+2sqrt(3)y+2=0x^(2)+y^(2)+4sqrt(3)y+2=0x^(2)+y^(2)-4sqrt(3)y+8=0 none of these

The locus of the mid-point of a chord of the circle x^2 + y^2 -2x - 2y - 23=0 , of length 8 units is : (A) x^2 + y^2 - x - y + 1 =0 (B) x^2 + y^2 - 2x - 2y - 7 = 0 (C) x^2 + y^2 - 2x - 2y + 1 = 0 (D) x^2 + y^2 + 2x + 2y + 5 = 0

An equation of the normal at the point (2,3)to the circle x ^(2)+ y^(2) - 2x - 2y - 3=0 is

Find the equation of the circle whose diameter is the common chord of the circles x^(2) + y^(2) + 2x + 3y + 1 = 0 and x^(2) + y^(2) + 4x + 3y + 2 = 0

The equation to the normal to the circle x^(2)+y^(2)-2x-2y-2=0 at the point (3,1) on it is

The equation of the line that touches the curves y=x|x| and x^2+(y-2)^2=4 , where x!=0, is (a)y=4sqrt(5)x+20 (b)y=4sqrt(3)-12 (c)y=0 (d) y=-4sqrt(5)x-20

An equilateral triangle whose two vertices are (-2, 0) and (2, 0) and which lies in the first and second quadrants only is circumscribed by a circle whose equation is : (B) sqrt(3)x^2 + sqrt(3)y^2 - 4x - 4 sqrt(3)y = 0 (C) sqrt(3)x^2 + sqrt(3)y^2 - 4y + 4 sqrt(3)y = 0 (D) sqrt(3)x^2 + sqrt(3)y^2 - 4y - 4 sqrt(3) = 0