The equation of the diameter of the circle `x^2 + y^2 + 4x + 4y-11=0`, which bisects the chord cut off by the circle on the line `2x-3y-3=0` is `3x+2y+10=0`. Statement 2 : The diameter of a circle is a chord of the circle of maximum length. (A) Both 1 and 2 are true and 2 is the correct explanation of 1 (B) Both 1 and 2 are true and 2 is not a correct explanation of 1 (C) 1 is true but 2 is false (D) 1 is false but 2 is true

x-y+b=0 is a chord of the circle x^2 + y^2 = a^2 subtending an angle 60^0 in the major segment of the circle. Statement 1 : b/a = +- sqrt(2) . Statement 2 : The angle subtended by a chord of a circle at the centre is twice the angle subtended by it at any point on the circumference. (A) Both 1 and 2 are true and 2 is the correct explanation of 1 (B) Both 1 and 2 are true and 2 is not a correct explanation of 1 (C) 1 is true but 2 is false (D) 1 is false but 2 is true

The line x+3y=0 is a diameter of the circle x^(2)+y^(2)-6x+2y=0

The line x+3y=0 is a diameter of the circle x^(2)+y^(2)+6x+2y=0

Equation of the chord of the circle x^(2) + y^(2) - 4x = 0 whose mid-point is (1,0) , is

If y = 2x + m is a diameter to the circle x^(2) + y^(2) + 3x + 4y - 1 = 0 , then find m

The midpoint of the chord y=x-1 of the circle x^(2)+y^(2)-2x+2y-2=0 is

If one of the diameters of the circle x^(2)+y^(2)-2x-6y+6=0 is a chord to the circle with centre (2,1), then the radius of circle is:

If one of the diameters of the circle x^(2)+y^(2)-2x-6y+6=0 is a chord to the circle with center (2,1) ,then the radius of the circle is