`3x - 2y + 1 = 0 and 2x - y = 0` are the equation of the sides `AB and AD` of the parallelogram `ABCD` and the equation of a diagonal of the parallelogram is `5x - 3y - 1 = 0`. The centroid of `DeltaABD` is : (A) `(1, 4/3)` (B) `(3, 14/3)` (C) `(7/3, 10/3)` (D) `(5/3, 8/3)`

3x - 2y + 1 = 0 and 2x - y = 0 are the equation of the sides AB and AD of the parallelogram ABCD and the equation of a diagonal of the parallelogram is 5x - 3y - 1 = 0 . The equation of the other diagonal of the parallelogram is : (A) x-y+1=0 (B) x-y-1=0 (C) 3x+5y+13=0 (D) 3x+5y=13

3x - 2y + 1 = 0 and 2x - y = 0 are the equation of the sides AB and AD of the parallelogram ABCD and the equation of a diagonal of the parallelogram is 5x - 3y - 1 = 0 . The area of the parallelogram ABCD is : (A) 2 sq. units (B) 4 sq. units (C) 6 sq. units (D) 8 sq. units

The equations of the sides of a parallelogram are x = 2, x = 3 and y = 1, y = 5. Equations to the pair of diagonals are

2x+3y-5=0,2x+3y+15=0,x+y-7=0,x+y+7=0 are sides of a parallelogram.Then the centre of the parallelogram is

If the adjacent sides of a parallelogram are 2x^(2)5x+3y^(2)=0 and one diagonal is

The sides AB and AD of a parallelogram ABCD are 2x-y+1=0 and x+3y-10=0 respectively and C is the point (-1, -2) . Find the equation of the diagonals AC and BD.

The diagonals of a parallelogram ABCD are along are the lines x+3y=4 and 6x-2y=7. Then ABCD must be a

The two adjacent sides of parallelogram are y =0 and y=sqrt(3)(x-1) .If equation of one diagonal is sqrt(3)y=(x+1), then equation of other diagonal is