On the parabola `y^2 = 4ax`, three points `E, F, G` are taken so that their ordinates are in geometrical progression. Prove that the tangents at `E and G` intersect on the ordinate passing through `F`.

If P, Q, R are three points on a parabola y^2=4ax whose ordinates are in geometrical progression, then the tangents at P and R meet on :

The tangent and normal at P(t), for all real positive t, to the parabola y^(2)=4ax meet the axis of the parabola in T and G respectively, then the angle at which the tangent at P to the parabola is inclined to the tangent at P to the circle passing through the points P, Tand G is

If the normals from any point to the parabola y^(2)=4x cut the line x=2 at points whose ordinates are in AP then prove that the slopes of tangents at the co-normal points are in G.P.

Prove that the tangents drawn on the parabola y^(2)=4ax at points x = a intersect at right angle.

If PQ is the focal chord of the parabola y^(2)=-x and P is (-4, 2) , then the ordinate of the point of intersection of the tangents at P and Q is

Let p be a point on the parabola y^(2)=4ax then the abscissa of p ,the ordinates of p and the latus rectum are in