Find the locus of the point through which pass three normals to the parabola `y^2 = 4ax` such that two of them make angles `alpha and beta` respectively with the axis so that `tan alpha tan beta = 2`.

The locus of the point through which pass three normals to the parabola y^(2)=4ax, such that two of them make angles alpha& beta respectively with the axis &tan alpha*tan beta=2 is (a>0)

Find the locus of the point N from which 3 normals are drawn to the parabola y^(2)=4ax are such that Two of them are equally inclined to x -axis

At the point of intersection of the curves y^2=4ax" and "xy=c^2 , the tangents to the two curves make angles alpha" and "beta respectively with x-axis. Then tan alpha cot beta=

The Locus of the point P when 3 normals drawn from it to parabola y^(2)=4ax are such that two of them makes complementary angles with X axis is

If two normals drawn from any point to the parabola y^(2) = 4ax make angle alpha and beta with the axis such that tan alpha . tan beta = 2, then find the locus of this point,

If the normals to the parabola y^(2)=4ax at P meets the curve again at Q and if PQ and the normal at Q make angle alpha and beta respectively,with the x-axis,then tan alpha(tan alpha+tan beta) has the value equal to 0 (b) -2( c) -(1)/(2)(d)-1

If the two lines ax^(2)+2hxy+by^(2)=a make angles alpha and beta with X-axis,then : tan(alpha+beta)=

If the lines represented by ax^(2)-bxy-y^(2)=0 makes angle alpha and beta with X-axis, then tan(alpha+beta)=

If the lines represented by the equation ax^(2)-bxy-y^(2)=0 make angles alpha and beta with the X-axis, then tan(alpha+beta)=