The line `lx+my+n=0` is a normal to the parabola `y^2 = 4ax` if

The line 1x+my+n=0 is a normal to the parabola y^(2)=4ax if :

Statement 1: The line ax+by+c=0 is a normal to the parabola y^(2)=4ax. Then the equation of the tangent at the foot of this normal is y=((b)/(a))x+((a^(2))/(b)). Statement 2: The equation of normal at any point P(at^(2),2at) to the parabola y^(2)= 4ax is y=-tx+2at+at^(3)

The line sqrt(2y)-2x+8a=0 is a normal to the parabola y^(2)=4ax at P ,then P=

The line sqrt(2)y-2x+8a=0 is a normal to the parabola y^(2)=4ax at P .then P =

If the line y=mx+c is a normal to the parabola y^2=4ax , then c is

The pole of the line lx+my+n=0 with respect to the parabola y^(2)=4ax, is

If the line Ix+my+n=0 is a tangent to the parabola y^(2)=4ax, then locus of its point of contact is:

The straight line lx+my+n=0 will touch the parabola y^2 = 4px if (A) lm^2 = np (B) mn=pl^2 (C) pn^2 = lm (D) none of these