Prove that the product of the perpendiculars from the foci upon any tangent to the ellipse `x^2/a^2+y^2/b^2=1` is `b^2`

Product of perpendiculars drawn from the foci upon any tangent to the ellipse 3x^(2)+4y^(2)=12 is

The product of perpendiculars from the focii upon any tangent of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 is b^(2)

The locus of the foot of the perpendicular from the foci an any tangent to the ellipse x^(2)/a^(2) + y^(2)/b^(2) = 1 , is

The product of the perpendiculars from the foci on any tangent to the hyperbol (x^(2))/(64)-(y^(2))/(9)=1 is

Prove that the product of the perpendicular from the foci on any tangent to an ellipse is equal to the square of the semi-minor axis.

The product of the perpendicular from two foci on any tangent to the hyperbola (x^(2))/(a^(2))-(y^(2))/(b^(2))=1 is (A)a^(2)(B)((b)/(a))^(2)(C)((a)/(b))^(2) (D) b^(2)

The locus of the foot of the perpendicular drawn from the centre on any tangent to the ellipse x^2/25+y^2/16=1 is: