The point on the line `x-y+ 2= 0` from which the tangent to the parabola `y^2= 8x` is perpendicular to the given line is `(a, b)`, then the line `ax + by+c=0` is

The point on the line x-y+2=0 from which the tangent to the parabola y^(2)=8x is perpendicular to the given labe is (a,b), then the line ax+by+c=0 is

The equation of a tangent to the parabola y^(2)=8x is y=x+2. The point on this line from which the other tangent to the parabola is perpendicular to the given tangent is

The equation of a tangent to the parabola y^(2)=12x is 2y+x+12=0. The point on this line such that the other tangent to the parabola is perpendicular to the given tangent is (a,b) then |a+b|=

The equation of the tangent to the parabola y^(2)=8x which is perpendicular to the line x-3y+8=0 , is

The equation of the tangent to the parabola y^(2)=16x, which is perpendicular to the line y=3x+7 is

if the line 2x-4y+5=0 is a tangent to the parabola y^(2)=4ax. then a is

Find the equaiton of the tangents to the hyperbola x^2 - 2y^2 = 18 which are perpendicular to the line x-y=0 .

If the line ax+by+c=0 is a tangent to the parabola y^(2)-4y-8x+32=0, then :