The eccentric angle of a point on the ellipse `x^2/6 + y^2/2 = 1` whose distance from the centre of the ellipse is 2, is (A) `pi/4` (B) `7pi/6` (C) `3pi/2` (D) `5pi/3`

Find the eccentric angle of a point on the ellipse (x^(2))/(6)+(y^(2))/(2)=1 whose distance from the center of the ellipse is sqrt(5)

Find the eccentric angle of a point on the ellipse x^2 + 3y^2 = 6 at a distance 2 units from the centre of the ellipse.

Eccentric angle of one of the points on the ellipse x^(2)+3y^(2)=6 at a distance 2 units from the centre of ellipse is k(pi)/(4), then k is:

The distance of a point on the ellipse x^2/6 + y^2/2 = 1 from the centre is 2. Find the eccentric angle of the point.

The eccentric angle of a point on the ellipse (x^(2))/(4)+(y^(2))/(3)=1 at a distance of 5/4 units from the focus on the positive x-axis is cos^(-1)((3)/(4)) (b) pi-cos^(-1)((3)/(4))pi+cos^(-1)((3)/(4))(d) none of these

The distance of a point on the ellipse (x^(2))/(6)+(y^(2))/(2)=1 from the centre is 2 Then the eccentric angle of the point is

There are exactly two points on the ellipse (x^2)/(a^2)+(y^2)/(b^2) =1 whose distance from the centre of the ellipse are equal to sqrt((3a^2-b^2)/(3)) . Eccentricity of this ellipse is

If the distance of a point on the ellipse (x^(2))/(6) + (y^(2))/(2) = 1 from the centre is 2, then the eccentric angle of the point, is

The angle between the planes 2x-y+z=6 and x+y+2z=7 is (A) pi/4 (B) pi/6 (C) pi/3 (D) pi/2