At the point of intersection of the curves `y^2=4ax" and "xy=c^2`, the tangents to the two curves make angles `alpha" and "beta` respectively with x-axis. Then `tan alpha cot beta=`

If the two lines ax^(2)+2hxy+by^(2)=a make angles alpha and beta with X-axis,then : tan(alpha+beta)=

Find the locus of the point through which pass three normals to the parabola y^2 = 4ax such that two of them make angles alpha and beta respectively with the axis so that tan alpha tan beta = 2 .

The locus of the point through which pass three normals to the parabola y^(2)=4ax, such that two of them make angles alpha& beta respectively with the axis &tan alpha*tan beta=2 is (a>0)

If the normals to the parabola y^(2)=4ax at P meets the curve again at Q and if PQ and the normal at Q make angle alpha and beta respectively,with the x-axis,then tan alpha(tan alpha+tan beta) has the value equal to 0 (b) -2( c) -(1)/(2)(d)-1

If the two lines 2x^(2)-3xy+y^(2)=0 makes anlges alpha and beta with X-axis then : csc^(2) alpha+csc^(2)beta=

If the lines represented by the equation 6x^(2)+41xy-7y^(2)=0 make angles alpha and beta with X-axis, then tan alpha.tan beta=

If the lines represented by ax^(2)-bxy-y^(2)=0 makes angle alpha and beta with X-axis, then tan(alpha+beta)=

If the lines represented by the equation ax^(2)-bxy-y^(2)=0 make angles alpha and beta with the X-axis, then tan(alpha+beta)=

If the lines represented by x^(2)-4xy+y^(2)=0 makes angle alpha and beta with X-axis, then tan^(2)alpha+tan^(2)beta=