The normal to the parabola `y^2 = 4ax` from the point `(5a, 2a)` are (A) `y=x-3a` (B) `y=-2x+12a` (C) `y=-3x+33a` (D) `y=x+3a`

The normals to the parabola y^(2)=4ax from the point (5a,2a) is/are

The normal to parabola y^(2) =4ax from the point (5a, -2a) are

Let L be a normal to the parabola y^(2)=4x. If L passes through the point (9,6), then L is given by y-x+3=0 (b) y+3x-33=0y+x-15=0( d ) y-2x+12=0

The normal to the curve x^(2)=4y passing (1,2) is (A) x+y=3 (B) x-y=3 (D) x-y=1

Show that the equation of the chord of the parabola y^2 = 4ax through the points (x_1, y_1) and (x_2, y_2) on it is : (y-y_1) (y-y_2) = y^2 - 4ax

Area bounded by the parabola y^2=x and the line 2y=x is (A) 4/3 (B) 1 (C) 2/3 (D) 1/3

The equation of the locus of points which are equidistant from the points (2,-3) and (3,-2) is (A) x+y=0 (B) x+y=7 (C) 4x+4y=38 (D) x+y=1

If x+y=k is a normal to the parabola y^(2)=12x then it touches the parabola y^(2)=px then

If a line x+ y =1 cut the parabola y^2 = 4ax in points A and B and normals drawn at A and B meet at C. The normals to the parabola from C other than above two meets the parabola in D, then point D is : (A) (a,a) (B) (2a,2a) (C) (3a,3a) (D) (4a,4a)

The area bounded by the parabola 4y=3x^(2) , the line 2y=3x+12 and the y - axis is