If `m` be the slope of common tangent to the circle `x^2 + y^2 = 16` and ellipse `x^2/25+y^2/4=1` in the first quadrant, then `81m^8 =`

Let m be slope of a common tangent to the circle x^2+y^2 = 4 and the ellipse x^2/6+y^2/3=1 , then m^2 equals ( sqrt2 =1.41 )

The number of common tangents of the circles x^(2) +y^(2) =16 and x^(2) +y^(2) -2y = 0 is :

The number of common tangents to the circles x^(2) + y^(2) = 4 and x^(2)+y^(2)-6x-8y=24 is

Find the number of common tangents to the circles x^2+y^2=4 and x^2+y^2-6x-8y=24

If l is the length of the intercept made by a common tangent to the circle x^2+y^2=16 and the ellipse (x^2)/(25)+(y^2)/(4)=1 , on the coordinate axes, then 81l^2+3 is equal to

A common tangent to the circles x^(2)+y^(2)=4 and (x-3)^(2)+y^(2)=1 , is

If m is the slope of a common tangent of the parabola y^(2)=16x and the circle x^(2)+y^(2)=8 , then m^(2) is equal to

Equation of a common tangent to the circle x^2+y^2=16 , parabola x^2=y-4 and the ellipse x^2/25+y^2/16=0 is