`int(5cosx-4sinx+1/cos^2x)dx`

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The value of int(cos2x)/(sinx+cosx)^(2) dx is equal to

" (8) "int(cosx-sinx)/(sin x+cos x)dx

int(cos2x)/(sinx+cosx)dx=

int sinx/(1-cos^2x)dx

int(cos2x)/((sinx+cosx)^(2))dx is equal to

int(cosx+sinx)/(sin x-cos x)dx=

I=inte^(cosx-sinx)(sin x+cos x)dx

int(cosx-sinx)/sqrt(8-sin2x)dx=Asin^(-1)((sinx+cosx)/B), (A,B)=