`intcos^3x/sqrt (sinx)dx`

Evaluate int cos^(3)x sqrt(sinx)dx .

intcos^3x/(sin^4x)dx=?

Evaluate the following : (i) int(x+(1)/(x))^(3//2)((x^(2)-1)/(x^(2)))dx " (ii) " int(sqrt(2+logx))/(x)dx (iii) int((sin^(-1)x)^(3))/(sqrt(1-x^(2)))dx " (iv) " int(cotx)/(sqrt(sinx))dx

int(cotx)/(sqrt(sinx))dx=

The value of int(sinx-cosx)/(sqrt(sin2x)dx is equal to

intcos^3x*e^(logsinx)dx

intcos^3x/(sin^2x+sinx)dx

intcosx/sqrt(sin^2x+3sinx+4)dx

I=int (sinx+cosx)/sqrt(1-sin2x) dx

int((sinx+cosx))/(sqrt(sin2x))dx