`intsecx/(b+atanx)dx`

intsecx/(secx+tanx)dx

I=int(sec^2x)/((b+atanx))dx

Evaluate: intsecx\ (secx+tanx)dx

(i) intsecx (secx +tanx) dx (ii) intcosec x(cosecx + cot x)dx

int x/(b+x)dx

intsec(ax+b)dx

intsecx/(sqrt(sin(2x+theta)+sin theta))dx(AA x,theta in(0,(pi)/(2))) (A) sqrt(3(tan x sec theta+tan theta sec theta))+c (B) sqrt(2(tan x sec theta+tan theta sec theta))+c (C) sqrt(5(tan x sec theta-tan theta sec theta))+c (D) sqrt((tan x sec theta-tan theta sec theta))+c

int_(b)^( a)x^(2)dx=

int (x-b)/(a+x)dx

If y=(a+btanx)/(b-atanx)," then "(dy)/(dx)=