Evaluate: `int(1+costheta)/(theta+sintheta)d theta`

Evaluate: inte^tantheta(sectheta-sintheta)d theta

The value of int(1+sin2theta)/(sintheta-costheta)d""theta is equal to

Prove that : (1-costheta)/(sintheta)+(sintheta)/(1-costheta)=2"cosec "theta

int(costheta-cos2theta)/(1-cos theta)d theta=

int(1-costheta)^2 d theta is equal to

int (cos2theta) . log((costheta+sintheta)/(costheta-sintheta))d theta is equal to

Evaluate : ( Cos^3theta + Sin^3theta ) / ( Costheta + Sintheta ) + ( Cos^3theta - Sin^3theta ) / ( Costheta - Sintheta )

int(costheta)/(7+sintheta-2cos^2theta)d theta is equal to

int(cos2theta)/((sintheta+costheta)^(2))d""theta is equal to