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Evaluate: inte^(ax)cosbxdx...

Evaluate: `inte^(ax)cosbxdx`

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Knowledge Check

  • inte^(ax)cosbx dx =

    A
    `(e^(ax))/r cos (bx-alpha)`
    B
    `(e^(ax))/r cos (bx+alpha)`
    C
    `(e^(ax))/r sin (bx-alpha)`
    D
    `(e^(ax))/r sin (nx+alpha)`
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