Find the value of `int_0^(2pi) |sinx|dx`

Find the value of int_0^(2pi) |cosx|dx

Find the value of int_0^(pi/2)(sinx.cosx)/((a^2cos^2x+b^2sin^2x)^2)dx

Find the value of int_0^(pi/2) cosx/(1+sinx)^2dx

The value of int_(0)^(2pi)|cosx-sinx|dx is equal to

The value of int_(0)^(16pi//3) |sinx|dx is

Evaluate: int_0^(2pi) [2sinx]dx

Evaluate : int_0^(pi/2) x sinx dx

(i) Show that int_(0)^(pi)xf(sinx)dx =(pi)/(2)int_(0)^(pi)f (sin x)dx. (ii) Find the value of int_(-1)^(3//2)|x sin pix|dx .

Evaluate -int_(2pi)^(0)|sinx|dx