`(dy)/(dx)tany=sin(x+y)+sin(x-y)`

(dy)/(dx)+y=sin x

(dy)/(dx)=sin(x-y)

x(dy)/(dx)+y=sin x

Statement-1: Solution of the differential equation dy/dx tany=sin(x+y)+sin(x-y) is secy+2cosx=c .Statement-2: The differential equation dy/dx tany=sin(x+y)+sin(x-y) is (A) Both 1 and 2 are true and 2 is the correct explanation of 1 (B) Both 1 and 2 are true and 2 is not correct explanation of 1 (C) 1 is true but 2 is false (D) 1 is false but 2 is true

(tany)(dy)/(dx)=sin(x+y)-sin(x-y) A) secy tany = 2 sin x+c B) log(cosy-coty)=2sin x+c C) log(secy+tany)=2sin x+c D) secy+tany=c.e^(sinx)

(dy) / (dx) = sin (x + y)

(dy) / (dx) tan y = sin (x + y) + sin (xy)

(dy) / (dx) -y = sin x

(dy)/(dx)=e^(-y)sin x+e^((x-y))