The slope of the tangent at any point on a curve is `lambda` times the slope of the line joining the point of contact to the origin. Formulate the differential equation and hence find the equation of the curve.

The slope of the tangent any point on a curve is lambda times the slope of the joining the point of contact to the origin. Formulate the differential equation and hence find the equation of the curve.

A curve is such that the length of the polar radius of any point on the curve is equal to the length of the tangent drawn at this point.Form the differential equation and solve it to find the equation of the curve.

A curve passes through the point (-2, 1) and at any point (x, y) of the curve, the slope of the tangent is twice the slope of the line segment joining the point of contact to the point (-4, -3). Find the equation of the curve.

The normal lines to a given curve at each point pass through (2,0) . The curve passes through (2,3) . Formulate the differential equation and hence find out the equation of the curve.

At any point (x,y) of a curve,the slope of the tangent is twice the slope of the line segment joining the point of contact to the point Find the equation of the curve given that it passes through quad (-2,1)

The slope of the tangent line to the curve x+y=xy at the point (2,2) is

A curve having the condition that the slope of the tangent at some point is two times the slope of the straight line joining the same point to the origin of coordinates is a/an

The tangents to a curve at a point on it is perpendicular to the line joining the point with the origin. Find the equation of the curve.

The tangents to a curve at a point on it is perpendicular to the line joining the point with the origin. Find the equation of the curve.

The slope of the tangent at any arbitrary point of a curve is twice the product of the abscissa and square of the ordinate of the point. Then, the equation of the curve is (where c is an arbitrary constant)